Binary Tree Level Order Traversal
Level order traversal is a method of visiting all nodes in a binary tree level by level, from top to bottom and left to right within each level. It's also known as Breadth-First Search (BFS) for trees.
How it works?
- Start at the root node (level 0)
- Visit all nodes at the current level before moving to the next level
- Within each level, nodes are visited from left to right
A
/ \
B C
/ \ \
D E F
The level order traversal would be: A, B, C, D, E, F
Problem Statement
Given the root of a binary tree, return the level order traversal of its nodes' values. (i.e., from left to right, level by level).
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number[][]}
*/
var levelOrder = function(root) {
if (!root) return [];
const result = [];
const queue = [root];
while (queue.length > 0) {
const levelSize = queue.length;
const currentLevel = [];
for (let i = 0; i < levelSize; i++) {
const node = queue.shift();
currentLevel.push(node.val);
if (node.left) queue.push(node.left);
if (node.right) queue.push(node.right);
}
result.push(currentLevel);
}
return result;
};
Explanation
Initialization:
- If the tree is empty (root === null), return an empty array.
- Initialize a result array to store the levels and a queue with the root node.
BFS Traversal
- While the queue is not empty:
- Get the current level's size (number of nodes at this level).
- Initialize a currentLevel array to store node values for this level.
- Process each node in the current level:
- Remove the node from the queue (shift).
- Add its value to currentLevel.
- Enqueue its left and right children (if they exist).
- Push currentLevel into result.
- While the queue is not empty:
Return result
- After processing all levels, return result.